Consider the following example:
#lang racket
(match '(cat . doge)
[`(,a . ,b)
(match b
[a #t]
[_ #f])]
[_ "Not a pair"])
This is what I might write if I wanted to match pairs where the head and tail are the same. This doesn't work though because the second a
is bound as a new variable (and matches anything). Are there any pattern forms which allow me to use the previously bound a
from the outer scope?
I know this can be achieved in the following way
(match* ('cat 'doge)
[(a a) #t]
[(_ _) #f])
but I still would like to know if there is a way to get that variable from the outer scope (or if there is a reason for not doing so, like some potential name collision problem or something).
Use ==
:
(match '(cat . doge)
[`(,a . ,b)
(match b
[(== a) #t]
[_ #f])]
[_ "Not a pair"])
Due to the placement in the docs, ==
is easy to overlook.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With