Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Can I tell browser-sync to always use one .html file? (for html5mode links)

I use browser-sync (https://github.com/shakyShane/browser-sync) in my gulp file for development purposes. I want to use html5mode within my angular app. For that server needs to route multiple url patterns to single html file. Staging and production servers already do that but I would also like to have this up and running during development.

Here is how I run browser-sync server (part of gulpfile.js):

gulp.task('serve', function () {
    browserSync.init(null, {
        server: {
            baseDir: [APP_PATH]
        }
    });

    // watch only for app specific codes;
    ...
});

Just to make it more clear, at my app js I instruct angular to use html5mode for routing:

$locationProvider.html5Mode(true);

Within my APP_PATH I have single index.html which is served when I access browser-sync server. What I need is that browser-sync serves this single file for each paths.

So for example if I try to reach /users/2 path starting from root path everything is fine; however if I refresh page or try to reach /users/2 directly, browser-sync tells that it cannot find proper document to serve - this is all good and understandable but I wonder if there is any way to tell browser-sync built-in server to serve one file only. If not, can anyone suggest other options? Should I simply run express server and tell browser-sync to proxy through it?

like image 425
lukaszb Avatar asked Jun 29 '14 09:06

lukaszb


People also ask

What does Browser Sync do?

Browser synchronization (often simply called sync) is a free cloud service provided by a web browser vendor for sharing settings and data across multiple installs. This is typically used to maintain a consistent browser setup on multiple devices. The user must be logged-in to their account to sync a browser.


1 Answers

You can use https://github.com/tinganho/connect-modrewrite.

var modRewrite  = require('connect-modrewrite');

gulp.task('serve', function () {
    browserSync.init(null, {
        server: {
            baseDir: [APP_PATH],
            middleware: [
                modRewrite([
                    '!\\.\\w+$ /index.html [L]'
                ])
            ]
        }
    });

   // watch only for app specific codes;
   ...
});
like image 55
rodrigopavezi Avatar answered Oct 14 '22 17:10

rodrigopavezi