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My question is: "Can I pass the result of an assignment to a function in c++?"
The reason I want to do this is that a variable has a specific type, e.g. "int" so I assign the value to the variable and pass the whole thing to the overloaded function that takes "int" as an argument.
The main reason for doing this is to make the code a bit smaller and easier to read, so instead of:
val = 2
function(val);
I get:
function(val = 2);
Is that ok? If so, is there a convention that says this is poor coding practice for some reason?
Thanks, fodder
516
Parameters in C functions There are two ways to pass parameters in C: Pass by Value, Pass by Reference.
We cannot pass the function as an argument to another function. But we can pass the reference of a function as a parameter by using a function pointer.
Function Call When calling a function with a function parameter, the value passed must be a pointer to a function. Use the function's name (without parentheses) for this: func(print); would call func , passing the print function to it.
A function can take parameters which are just values you supply to the function so that the function can do something utilising those values. These parameters are just like variables except that the values of these variables are defined when we call the function and are not assigned values within the function itself.
Yes
Per paragraph § 5.17 / 1
The assignment operator (=) and the compound assignment operators all group right-to-left. All require a modifiable lvalue as their left operand and return an lvalue referring to the left operand.
After function(val = 2), 2 assigns to val then the value of val passes to the function.
Talking about readability is not easy, I personally don't use this way in my codes.
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