I am comparing the output of two programs, one C the other C++, using diff
, so the output must be identical.
Is there any way to printf
a double so that it is formatted as though it was printed using << mydouble
.
I am currently using printf("%g",mydouble)
Here are some examples of the differences:
c: 3.24769e-05 c++: 3.2477e-05
c: 0.0026572 c++: 0.00265721
Interestingly the scientific notation has more digits in c, and the decimal notation has more in c++.
The C++ printf() function is usually used in C programming but can also run in C++.
You can solve this by using the format specifiers in C.
For example, say you would like to print out only 3 places after the decimal, you could make your printf like so:
printf("%.3lf", dub);
With a value of double dub = .0137;
the output would be 0.014
This would fix the issue with your 2nd case if you want more precision printed you could write:
printf("%.8lf", dub);
Your output for double dub = 0.00265721;
would then be 0.00265721
The case for %g works the same way except the number on the left is included in the calculation. If you wanted the C++ version (the lesser precision I assume) then your code would look like this:
double dub = .0000324769;
printf("%.5g", dub);
Which yields 3.2477e-05
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