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Is there a way to destruct a structure (not a class)?
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You are allowed to include something called a destructor in a structure type definition. Any time a structured value of that type is destroyed, either automatically or explicitly, the destructor is run on the structured value first. Typically, the destructor deallocates memory.
So if there is a way to "destruct" a class, you can use the exact same way to "destruct" a structure. So, if you have a struct s { } in your C++ program you can do this: s *v = new s(); delete v; // will call structure's destructor. Or just letting an object fall out of scope will call the destructor.
Implicitly-declared destructor If no user-declared prospective (since C++20) destructor is provided for a class type (struct, class, or union), the compiler will always declare a destructor as an inline public member of its class.
In C++ a struct is exactly the same as a class with the exception of the default visibility on members and bases. So if there is a way to "destruct" a class, you can use the exact same way to "destruct" a structure.
So, if you have a struct s { } in your C++ program you can do this:
s *v = new s();
delete v; // will call structure's destructor.
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