Can I break a try - catch in JS without throwing exception?

Question

I'd like to silently break a try - catch in the try block if a condition applies. ( Without throwing an unneccessary exception )

foo = function(){

    var bar = Math.random() > .5;

    try{

          if( bar ) // Break this try, even though there is no exception here.

          //  This code should not execute if !!bar 

          alert( bar );

    }
    catch( e ){}

    // Code that executes if !!bar

    alert( true );

}

foo();

However, return is not an option, since the function is supposed to continue executing afterwards.

UPDATE

I'd like to still keep up the opportunity to use the finally block.

Answer 1

You can label a block and break from it using the break label syntax

as per your edit, finally is still executed

foo = function(){
    var bar = Math.random() > .5;
    omgalabel: try {
        if( bar ) break omgalabel;
        console.log( bar );
        // code 
    }
    catch( e ){
        //  This code should not execute if !!bar 
    }
    finally {
        // Code that executes no matter what
        console.log( true );
    }
}