Can changes in the order of the method parameters be called method overloading?

Question

Please note that only order of the parameters are changed in below example. So my question is - Can we call below example is of method overloading?

public void show(String s, int a){
    System.out.println("Test.show(String, int)");
}
public void show(int s, String a){
    System.out.println("Test.show(int, String)");
}

Answer 1

Yes, that's absolutely method overloading.

From section 8.4.9 of the JLS:

If two methods of a class (whether both declared in the same class, or both inherited by a class, or one declared and one inherited) have the same name but signatures that are not override-equivalent, then the method name is said to be overloaded.

"Override-equivalent" is described in section 8.4.2:

Two methods have the same signature if they have the same name and argument types.

[ ... Details on "same argument types ... ]

The signature of a method m1 is a subsignature of the signature of a method m2 if either:

• m2 has the same signature as m1, or

• the signature of m1 is the same as the erasure (§4.6) of the signature of m2.

Two method signatures m1 and m2 are override-equivalent iff either m1 is a subsignature of m2 or m2 is a subsignature of m1.