Can a sass @mixin accept an undefined number of arguments?

Question

I'm trying to create a sass mixin for transitions. This is what I have so far.

@mixin transition($var)   -webkit-transition: $var   transition: $var 

I want to be able to pass it multiple arguments like this

@include transition(color .5s linear, width .5s linear) 

Unfortunately, I get the following error

Syntax error: Mixin transition takes 1 argument but 2 were passed. 

Is there a way to do this so it produces the following output in css while still accepting an undefined number of arguments?

-webkit-transition: color .5s linear, width .5s linear; transition: color .5s linear, width .5s linear; 

Answer 1

Variable Arguments

Sometimes it makes sense for a mixin to take an unknown number of arguments. For example, a mixin for creating box shadows might take any number of shadows as arguments. For these situations, Sass supports “variable arguments,” which are arguments at the end of a mixin declaration that take all leftover arguments and package them up as a list. These arguments look just like normal arguments, but are followed by .... For example:

@mixin box-shadow($shadows...) {   -moz-box-shadow: $shadows;   -webkit-box-shadow: $shadows;   box-shadow: $shadows; }  .shadows {   @include box-shadow(0px 4px 5px #666, 2px 6px 10px #999); } 

is compiled to:

.shadows {   -moz-box-shadow: 0px 4px 5px #666, 2px 6px 10px #999;   -webkit-box-shadow: 0px 4px 5px #666, 2px 6px 10px #999;   box-shadow: 0px 4px 5px #666, 2px 6px 10px #999; } 

From : SASS official Documentation

So you basically just need to change your mixins declaration to look like this :

@mixin transition($var...)   -webkit-transition: $var   transition: $var