Can a function marked as noexcept have exceptions inside?

Question

Let's say that I have a function marked as noexcept but there's a line of code inside that can throw. That line of code will be in a try block and the exception will be caught. Does that cause anything?

void MyFunc() noexcept
{
    try {
        throw std::exception("...");
    } catch (const std::exception & e) {
        // I'll deal with it here...
    }
}