Can a constructor function be a friend in c++?

Question

Can we declare constructor of a class to be friend? I think it cannot be. But i read somewhere that it can be, but i was unable to do. If yes can you please provide some example code.

Answer 1

Yes it can:

class Y { public:      Y(); }; class X { private:      void foo() {}        friend Y::Y(); }; Y::Y()  {    X x; x.foo();  }   

As per 11.3 Friends [class.friend]

5) When a friend declaration refers to an overloaded name or operator, only the function specified by the parameter types becomes a friend. A member function of a class X can be a friend of a class Y.

[ Example:

class Y { friend char* X::foo(int); friend X::X(char); // constructors can be friends friend X::~X(); // destructors can be friends }; 

—end example ]

(emphasis mine)