Is is possible to do something like <code>super.super</code> in the overriden method? That is, to bypass the direct parent's super and call "grandparent's" super?

This is not recommended, but what you want is possible like this: <pre class="prettyprint"><code>grandparent = self.class.superclass.superclass meth = grandparent.instance_method(:the_method) meth.bind(self).call </code></pre> This works by first getting the grandparent class, then calling <code>instance_method</code> on it to get an <code>UnboundMethod</code> representing the grandparent's version of <code>the_method</code>. It then uses <code>UnboundMethod#bind</code> and <code>Method#call</code> to call the grandparent's method on the current object.

Calling super's super method

1 Answers

This is not recommended, but what you want is possible like this:

grandparent = self.class.superclass.superclass
meth = grandparent.instance_method(:the_method)
meth.bind(self).call

This works by first getting the grandparent class, then calling instance_method on it to get an UnboundMethod representing the grandparent's version of the_method. It then uses UnboundMethod#bind and Method#call to call the grandparent's method on the current object.