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Consider the following:
class MyClass { public: int operator ()(int a, int b); }; When having:
MyClass* m = new MyClass(); I want to access the operator() method, so I could:
(*m)(1,2); But can I do this?
m->(1,2); 
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There is no way to override operators on them. Pointers are (like char, int, float, etc...) a native type. You can create an object that behaves like a pointer and overload operators [->, *], but that will not overload [->, *] on the the native pointer.
This means C++ has the ability to provide the operators with a special meaning for a data type, this ability is known as operator overloading. For example, we can overload an operator '+' in a class like String so that we can concatenate two strings by just using +.
An overloaded operator (except for the function call operator) cannot have default arguments or an ellipsis in the argument list. You must declare the overloaded = , [] , () , and -> operators as nonstatic member functions to ensure that they receive lvalues as their first operands.
The function call operator, when overloaded, does not modify how functions are called. Rather, it modifies how the operator is to be interpreted when applied to objects of a given type.
Not with that syntax, but you can do
m->operator()(1,2); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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