calling child class method from parent class file in python

Question

parent.py:

class A(object):     def methodA(self):         print("in methodA") 

child.py:

from parent import A class B(A):     def methodb(self):         print("am in methodb") 

Is there anyway to call methodb() in parent.py?

Answer 1

Doing this would only make sense if A is an abstract base class, meaning that A is only meant to be used as a base for other classes, not instantiated directly. If that were the case, you would define methodB on class A, but leave it unimplemented:

class A(object):     def methodA(self):         print("in methodA")      def methodB(self):         raise NotImplementedError("Must override methodB")   from parent import A class B(A):     def methodB(self):         print("am in methodB") 

This isn't strictly necessary. If you don't declare methodB anywhere in A, and instantiate B, you'd still be able to call methodB from the body of methodA, but it's a bad practice; it's not clear where methodA is supposed to come from, or that child classes need to override it.

If you want to be more formal, you can use the Python abc module to declare A as an abstract base class.

from abc import ABC, abstractmethod  class A(ABC):      def methodA(self):         print("in methodA")      @abstractmethod     def methodB(self):         raise NotImplementedError("Must override methodB") 

Or if using Python 2.x:

from abc import ABCMeta, abstractmethod  class A(object):  __metaclass__ = ABCMeta      def methodA(self):         print("in methodA")      @abstractmethod     def methodB(self):         raise NotImplementedError("Must override methodB") 

Using this will actually prevent you from instantiating A or any class that inherits from A without overriding methodB. For example, if B looked like this:

class B(A):    pass 

You'd get an error trying to instantiate it:

Traceback (most recent call last):   File "<stdin>", line 1, in <module> TypeError: Can't instantiate abstract class B with abstract methods methodB 

The same would happen if you tried instantiating A.

Answer 2

You can do something like this:

class A():     def foo(self):         self.testb()  class B(A):     def testb(self):         print('lol, it works') b = B() b.foo() 

Which would return this of course:

lol, it works 

Note, that in fact there is no call from parent, there is just call of function foo from instance of child class, this instance has inherited foo from parent, i.e. this is impossible:

a=A() a.foo() 

will produce: AttributeError: A instance has no attribute 'testb'

because

>>> dir(A) ['__doc__', '__module__', 'foo'] >>> dir(B) ['__doc__', '__module__', 'foo', 'testb'] 

What I've wanted to show that you can create instance of child class, and it will have all methods and parameters from both parent and it's own classes.