Calling C# function with multiple arguments from F#

Question

It is easy to call f:Func<'T, 'T> from F# as 'T -> 'T by using f.Invoke

But how should I call f:Func<'T, 'T, 'T> from F# as 'T -> 'T -> 'T?

When I use f.Invoke I get 'T * 'T -> 'T, i.e. a tuple instead of two arguments.

Answer 1

Try:

let g = f.Invoke |> FuncConvert.FuncFromTupled