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The following code runs in PHP
<?php
$foo = "Chocolate milkshake";
go($foo);
function go($param) {
echo $param;
}
?>
// Output: chocolate milkshake
See this Demo http://codepad.viper-7.com/ToApZa
This code runs without errors and prints specified output, why? I thought this "function hoisting" only occurred in JavaScript
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However, functions go out of this route as they are read first, but only the function head (= first line). That is why function calls are possible before declaration.
With JavaScript functions, it is possible to call functions before actually writing the code for the function statement and they give a defined output. This property is called hoisting.
A common error is defining a function but forgetting to call the function. A function does not automatically get executed. A function that does not explicitly return a value returns the JavaScript value undefined.
declare and define are the same, and they mean when you write all the code for your function. At that point the function just sits there doing nothing. call is when you tell the JavaScript interpreter to run the code in your function.
It doesn't matter where you declare your functions in PHP in most cases, as you've just proved :)
Take a look at this page for more details. The key point:
Functions need not be defined before they are referenced, except when a function is conditionally defined as shown in the two examples below.
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