I would like to know If I can call a child's object in a parent function. Like this:
class Parent {
public function A() {
<< I want to call the object here >>
// Some code
}
}
Class Child extends Parent {
public function B() {
// Some code
}
}
$Child = new Child();
$Child -> B();
The two classes are in different files. My Child class is making a connection with my database with function B(). In my Parent's class, A(), I am trying to insert data I receive from filling a form, but I need a connection to the database and I do not know how I can call that object. Note: My code is working when I have both functions in the same Class.
I did not find the solution, so I will try and post my real code:
class db_connect extends Model
{
private $dbname = "...";
private $dbuser = "...";
private $dbpass = "...";
private $dbhost = "...";
public $dbc;
public function Connect()
{
$this->dbc = mysqli_connect($this->dbhost, $this->dbuser, $this->dbpass, $this->dbname);
if($this->dbc === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}}
}
So this was the Class Child from Above and Connect() was B().
Now the parent
class Model
{
public $query;
public $result;
public function proccess_data($marca,$model,$pret,$descriere){
<< I am trying to make a connection here from config.php using the function Connect() >>
$this->query = "INSERT INTO autoturisme (autoturism_id, marca, model, pret, descriere) " .
"VALUES (NULL, '$marca', '$model', '$pret', '$descriere')";
$this->result = mysqli_query(<<Also here I would need the connection>>, $this->query)
or die(mysqli_error(<<And here>>));
if($this->result == 1){
echo "<br/>Your data were processed";
} else {
echo "<br/>We are sorry but an error occurred";
}
$this->close_db();
}
In the mysqli_query I need a parameter as a mysqli, which is the connection to my database. The parameter is in the Child's Class, $dbc, and it is called in the function Connect() with: $this->dbc . Same goes for mysqli_error. Hope this makes things clearer :).
Considering you have tagged this oop I will bite.
There is no reason for something called db_connect
to ever extend something called Model
. Not to mention there is no reason to call something Model
which doesn't tell anybody anything and as such is a pretty crappy name for anything.
Secondly as far as I can see there is no reason for you to wrap mysqli
to begin with. What do you gain by wrapping an object like that. mysqli
comes with an object-oriented interface out of the box.
Finally when you get rid of that odd inheritance tree you have going on you should inject the database connection into the classes that need it. Something like:
class Car
{
// why do you need a `$query` member when you are not going to use it?
// same for `$result`
private $dbConnection;
public function __construct(mysqli $dbConnection)
{
$this->dbConnection = $dbConnection;
}
public function add($marca, $model, $pret, $descriere)
{
$query = 'INSERT INTO autoturisme';
$query.= ' (marca, model, pret, descriere)';
$query.= ' VALUES';
$query.= ' (?, ?, ?, ?)';
$stmt = $this->dbConnection->prepare($query);
$stmt->bind_param('ssss', $marca, $model, $pret, $descriere);
if (!$stmt->execute()) {
throw new \Exception('We are sorry but an error occurred');
}
}
}
$mysqli = new mysqli('localhost', 'user', 'pass', 'dbname');
$car = new Car($mysqli);
try {
$car->add('BMW', '325', 'dunnowhatthismeans', 'description?');
} catch(\Exception $e) {
echo $e->getMessage();
}
Also note that your code is most likely vulnerable to SQL injection.
You should not ideally call a child's function from an instance of the parent class. This is something that should not be done.
Instead you can override the function in the child class and then call the method from the instance of the child class.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With