Call Method overloaded from abstract class

Question

I need to call a Method of a an abstract class implementation. But the compiler always defaults to use the overloaded method from the concrete class, since the signature just requires an inherited type.

Just have a look at the code:

-- This is obviously a vastly simplified version of the actual code that I'm using ;)

public class ModelBase { }
public class ModelA : ModelBase { }
public interface IInterface<in TModel>
{
    void Do(TModel model);
}
public abstract class AbstractClass<TModel> : IInterface<TModel>
{
    public abstract void Do(TModel model);
}
public class ConcreteClass : AbstractClass<ModelA>, IInterface<ModelBase>
{
    public override void Do(ModelA model)
    {
        // I'd like to invoke this method
    }

    public void Do(ModelBase model)
    {
        // how do I invoke the method above??
        Do((ModelA)model);
    }
}

^^ This results in a recursion

What I've tried is:

((IClass<ModelA>)this).Do((ModelA)model);

^^ doesn't change anything

base.Do((ModelA)model);

^^ throws an error "Cannot call an abstract base member: 'AbstractClass.Do(ModelA)'"

How do I call the "public override void Do(ModelA model)" method?

---

btw. If I change the class to this

public class ConcreteClass : IInterface<ModelA>, IInterface<ModelBase>

it works.

Answer 1

Cast this to AbstractClass<ModelA> before call:

public void Do(ModelBase model)
{
    ((AbstractClass<ModelA>)this).Do((ModelA)model);
}

Answer 2

Use named parameters:

public class ConcreteClass : AbstractClass<ModelA>, IInterface<ModelBase>
{
    public override void Do(ModelA modelA) // change 'model' into 'modelA'
    {
        // I'd like to invoke this method
    }

    public void Do(ModelBase model)
    {
        // how do I invoke the method above??
        Do(modelA : (ModelA)model);
    }
}

Now, the compiler knows that you want to call the Do(ModelA) method and not the Do(ModelBase) method.