Call a function outside main () [duplicate]

Question

I'm trying to do this:

#include <iostream>
using namespace std;

class smth {
  public:
  void function1 () { cout<<"before main";}
  void function2 () { cout<<"after main";}
};

call function1();

int main () 
{
  cout<<" in main";
  return 0;
}
call funtion2();

and i want to have this message: " before main" " in main" "after main"

How can I do it?

Answer 1

You can't. At least not that way. You should be able to solve it by putting the code in a class constructor and destructor, then declaring a global variable:

struct myStruct
{
    myStruct() { std::cout << "Before main?\n"; }
    ~myStruct() { std::cout << "After main?\n"; }
};

namespace
{
    // Put in anonymous namespace, because this variable should not be accessed
    // from other translation units
    myStruct myStructVariable;
}

int main()
{
    std::cout << "In main\n";
}