Calculating value using previous value of a row in T-SQL

Question

I got following table and want to calculate value of Column2 on each row using the value of the same column (Column2) from the previous row in a sql without using cursor or while loop.

Id   Date             Column1    Column2
1    01/01/2011       5          5 => Same as Column1
2    02/01/2011       2          18 => (1 + (value of Column2 from the previous row)) * (1 + (Value of Column1 from the current row)) i.e. (1+5)*(1+2)
3    03/01/2011       3          76 => (1+18)*(1+3) = 19*4
and so on

Any thoughts?

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Answer 1

Assuming at least SQL Server 2005 for the recursive CTE:

;with cteCalculation as (
    select t.Id, t.Date, t.Column1, t.Column1 as Column2
        from YourTable t
        where t.Id = 1
    union all
    select t.Id, t.Date, t.Column1, (1+t.Column1)*(1+c.Column2) as Column2
        from YourTable t
            inner join cteCalculation c
                on t.Id-1 = c.id
)
select c.Id, c.Date, c.Column1, c.Column2
    from cteCalculation c

Answer 2

I solved the problem, just mentioned.

This is my code:

;with cteCalculation as (
    select t.Id, t.Column1, t.Column1 as Column2
        from table_1 t
        where t.Id = 1
    union all
    select t.Id, t.Column1, (1+t.Column1)*(1+c.Column2) as Column2
        from table_1 t
            inner join cteCalculation c
                on t.Id-1 = c.id
),
cte2 as(
select t.Id, t.Column1 as Column3
        from table_1 t
        where t.Id = 1
    union all
    select t.Id, (select column2+1 from cteCalculation c where c.id = t.id)  as Column3
        from table_1 t
            inner join cte2 c2
                on t.Id-1 = c2.id
)

select c.Id, c.Column1, c.Column2, c2.column3
    from cteCalculation c
inner join cte2 c2 on c.id = c2.id

The result is as I was expected:

1           5   5   5
2           2   18  19
3           3   76  77