I'm having a hard time wrapping my head around some Trigonometry. I am trying to deduce a destination latitude and longitude from a start lat and log and distance and bearing.
Fortunately, I found an amazing site which describes exactly the function I need: http://www.movable-type.co.uk/scripts/latlong.html " Destination point given distance and bearing from start point " I tried it in my java program but it is not working for me. I deployed it as the website said. Here is my code:
double dist = 150/6371;
double brng = Math.toRadians(90);
double lat1 = Math.toRadians(26.88288045572338);
double lon1 = Math.toRadians(75.78369140625);
double lat2 = Math.asin( Math.sin(lat1)*Math.cos(dist) + Math.cos(lat1)*Math.sin(dist)*Math.cos(brng) );
double a = Math.atan2(Math.sin(brng)*Math.sin(dist)*Math.cos(lat1), Math.cos(dist)-Math.sin(lat1)*Math.sin(lat2));
System.out.println("a = " + a);
double lon2 = lon1 + a;
lon2 = (lon2+ 3*Math.PI) % (2*Math.PI) - Math.PI;
System.out.println("Latitude = "+Math.toDegrees(lat2)+"\nLongitude = "+Math.toDegrees(lon2));
But it shows the output is:
a = 0.0
Latitude = 26.882880455723377
Longitude = 75.78369140625
I am not getting where i am doing the mistake. Please anybody can help me to find out the problem.
Thanx in Advance. :-)
Here is the formula to find the second point, when first point, bearing and distance is known: latitude of second point = la2 = asin(sin la1 * cos Ad + cos la1 * sin Ad * cos θ), and. longitude of second point = lo2 = lo1 + atan2(sin θ * sin Ad * cos la1 , cos Ad – sin la1 * sin la2)
from math import cos, asin, sqrt, pi def distance(lat1, lon1, lat2, lon2): p = pi/180 a = 0.5 - cos((lat2-lat1)*p)/2 + cos(lat1*p) * cos(lat2*p) * (1-cos((lon2-lon1)*p))/2 return 12742 * asin(sqrt(a)) #2*R*asin...
The distance formula is: √[(x₂ - x₁)² + (y₂ - y₁)²]. This works for any two points in 2D space with coordinates (x₁, y₁) for the first point and (x₂, y₂) for the second point.
Your problem is on your first line.
Try
double dist = 150.0 / 6371.0;
The reason is that 150/6371
gets calculated as 0
, because it performs integer division (rather than floating point division). This is true even though the result is being stored in a double
. You can force floating point division by making one of the two numbers a floating point literal.
if anyone needs a function that calculates point coordinates from other point moved by some distance, below is the working code. For me, it's just moving a point by some distance.
import static java.lang.Math.*;
void movePoint(double latitude, double longitude, double distanceInMetres, double bearing) {
double brngRad = toRadians(bearing);
double latRad = toRadians(latitude);
double lonRad = toRadians(longitude);
int earthRadiusInMetres = 6371000;
double distFrac = distanceInMetres / earthRadiusInMetres;
double latitudeResult = asin(sin(latRad) * cos(distFrac) + cos(latRad) * sin(distFrac) * cos(brngRad));
double a = atan2(sin(brngRad) * sin(distFrac) * cos(latRad), cos(distFrac) - sin(latRad) * sin(latitudeResult));
double longitudeResult = (lonRad + a + 3 * PI) % (2 * PI) - PI;
System.out.println("latitude: " + toDegrees(latitudeResult) + ", longitude: " + toDegrees(longitudeResult));
}
You can change the radius to 6371 if you want to have the input in kilometres or to miles if you want to have input in miles.
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