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Is it possible to calculate the value of the mathematical constant, e with high precision (2000+ decimal places) using Python?
I am particularly interested in a solution either in or that integrates with NumPy or SciPy.
880
Using “%”:- “%” operator is used to format as well as set precision in python. This is similar to “printf” statement in C programming. Using format():- This is yet another way to format the string for setting precision.
The exp() function in Python allows users to calculate the exponential value with the base set to e. Note: e is a Mathematical constant, with a value approximately equal to 2.71828.
Use math.Call math. log(x) to return the natural logarithm of x .
Python Decimal default precision The Decimal has a default precision of 28 places, while the float has 18 places.
You can set the precision you want with the decimal built-in module:
from decimal import *
getcontext().prec = 40
Decimal(1).exp()
This returns:
Decimal('2.718281828459045235360287471352662497757')
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