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Calculate time difference (difftime) between columns of different rows

I have data on 'Start' and 'End' time for different jobs, grouped by 'owner':

Data <- data.frame(
  job = c(1, 2, 3, 4, 5),
  owner = c("name1", "name2", "name1", "name1", "name2"),
  Start = as.POSIXct(c("2015-01-01 15:00:00", "2015-01-01 15:01:00", "2015-01-01 15:13:00", "2015-01-01 15:20:00", "2015-01-01 15:39:02"), format="%Y-%m-%d %H:%M:%S"),
  End =   as.POSIXct(c("2015-01-01 15:11:11", "2015-01-01 15:17:21", "2015-01-01 15:17:00", "2015-01-01 15:31:21", "2015-01-01 15:40:11"), format="%Y-%m-%d %H:%M:%S")
)

For each owner, I want to calculate the idle time between the jobs for each owner, i.e. the difference between the 'End' time of one job and the 'Start' time of the next job.

How do I use difftime() to calculate this time difference between specific rows and times in different columns?

The result should look something like this:

job, owner, idletime
1, name1, NA
2, name2, NA
3, name1, 1.816667  # End of row 1 minus Start of row 3
4, name1, 3.0       # End of row 3 minus Start of row 4
...
like image 797
tobias_ Avatar asked Jan 29 '26 12:01

tobias_


1 Answers

Here's a possible solution using data.table

library(data.table) # v 1.9.5+
setDT(Data)[, idletime := difftime(Start, shift(End), units = "mins"), by = owner]
#    job owner               Start                 End       idletime
# 1:   1 name1 2015-01-01 15:00:00 2015-01-01 15:11:11        NA mins
# 2:   2 name2 2015-01-01 15:01:00 2015-01-01 15:17:21        NA mins
# 3:   3 name1 2015-01-01 15:13:00 2015-01-01 15:17:00  1.816667 mins
# 4:   4 name1 2015-01-01 15:20:00 2015-01-01 15:31:21  3.000000 mins
# 5:   5 name2 2015-01-01 15:39:02 2015-01-01 15:40:11 21.683333 mins

Or using dplyr

library(dplyr)
Data %>%
  group_by(owner) %>%
  mutate(idletime = difftime(Start, lag(End), units = "mins"))

# Source: local data frame [5 x 5]
# Groups: owner
# 
#   job owner               Start                 End       idletime
# 1   1 name1 2015-01-01 15:00:00 2015-01-01 15:11:11        NA mins
# 2   2 name2 2015-01-01 15:01:00 2015-01-01 15:17:21        NA mins
# 3   3 name1 2015-01-01 15:13:00 2015-01-01 15:17:00  1.816667 mins
# 4   4 name1 2015-01-01 15:20:00 2015-01-01 15:31:21  3.000000 mins
# 5   5 name2 2015-01-01 15:39:02 2015-01-01 15:40:11 21.683333 mins
like image 160
David Arenburg Avatar answered Feb 01 '26 01:02

David Arenburg



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