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c++11 struct initialization compilation error

Tags:

c++

c++11

struct SS {int a; int s;};

int main ()
{
   vector<SS> v;
   v.push_back(SS{1, 2});
}

The code can be compiled without any error. However, when the struct is initialized in class, I got compilation error. Can anyone explain it?

struct SS {int a = 0; int s = 2;};

Error:

In function ‘int main()’:
error: no matching function for call to ‘SS::SS(<brace-enclosed initializer list>)’
     v.push_back(SS{1, 2});
                        ^
note: candidates are:
note: constexpr SS::SS()
 struct SS {int a = 0; int s = 2;};
        ^
note:   candidate expects 0 arguments, 2 provided
note: constexpr SS::SS(const SS&)
note:   candidate expects 1 argument, 2 provided
note: constexpr SS::SS(SS&&)
note:   candidate expects 1 argument, 2 provided
like image 930
Michael D Avatar asked Aug 12 '13 09:08

Michael D


2 Answers

In C++11, when you use non static data member initialization at the point of declaration like you do here:

struct SS {int a = 0; int s = 2;};

you make the class a non-aggregate. This means you can no longer initialize an instance like this:

SS s{1,2};

To make this initialization syntax work for a non-aggregate, you would have to add a two-parameter constructor:

struct SS 
{
  SS(int a, int s) : a(a), s(s) {}
  int a = 0; 
  int s = 2;
};

This restriction has been lifted in C++14.

Note that you may want to add a default constructor for the class. The presence of a user-provided constructor inhibits the compiler generated default one.

See related reading here.

like image 53
juanchopanza Avatar answered Oct 22 '22 23:10

juanchopanza


Use of a default member initializer renders the class/struct a non-aggregate:

§ 8.5.1 Aggregates

An aggregate is an array or a class (Clause 9) with no user-provided constructors (12.1), no brace-or-equal-initializers for non-static data members (9.2), no private or protected non-static data members (Clause 11), no base classes (Clause 10), and no virtual functions (10.3).

Semantics differ for aggregates and non-aggregates:

Aggregates (e.g., arrays and structs):

Initialize members/elements beginning-to-end.

Non-aggregates:

Invoke a constructor.

v.push_back(SS{1, 2}); // Error, it tries to call SS constructor

Which means you need a constructor now:

struct SS 
{
  SS(int a, int s) : a(a), s(s) 
  {
  }
  int a = 0; 
  int s = 2;
};
like image 41
billz Avatar answered Oct 22 '22 21:10

billz