I have a bit of a weird problem here! I am trying to write the color table for a 8 bit windows 3.x bitmap file. I just want the file to be greyscale, so i am trying to write bbb0, ggg0, rrr0 256 times where r=g=b=1..256
//write greyscale color table
for (int i = 255; i >= 0; i--) {
writeS = (unsigned short)i;
outfile.write ((char*)&writeS,sizeof(char)); // b
outfile.write ((char*)&writeS,sizeof(char)); // g
outfile.write ((char*)&writeS,sizeof(char)); // r
writeS = 0;
outfile.write ((char*)&writeS,sizeof(char)); // 0
}
When I look at the output i am getting with a hex editor, everything looks fine until I get to the number 10, which is written like so:
...0C 0C 0C 00 0B 0B 0B 00 0D 0A 0D 0A 0D 0A 00 09 09 09 00 08 08 08 00...
isntead of:
...0C 0C 0C 00 0B 0B 0B 00 0A 0A 0A 00 09 09 09 00 08 08 08 00...
So that is wierd that it is only doing it on this one number, but what is even wierder is that when I change the code to skip the number 10 and write 9 instead, it works.
//write greyscale color table
for (int i = 255; i >= 0; i--) {
writeS = (unsigned short)i;
if (writeS == 10) writeS = 9;
outfile.write ((char*)&writeS,sizeof(char)); // b
outfile.write ((char*)&writeS,sizeof(char)); // g
outfile.write ((char*)&writeS,sizeof(char)); // r
writeS = 0;
outfile.write ((char*)&writeS,sizeof(char)); // 0
}
gives:
...0C 0C 0C 00 0B 0B 0B 00 09 09 09 00 09 09 09 00 08 08 08 00...
Is there something weird going on there with notation? Any obvious errors that I have missed? Has anyone ran into something like this before? Thanks!
The "number 10" in ASCII is the line feed character, \n
. In C++, this is the newline character.
You have apparently opened the file as a text stream. Because newlines are represented differently on different platforms, text streams perform newline translation: when reading they translate the platform-specific newline representation into \n
and when writing they translate the \n
character into the platform-specific newline representation.
On Windows, line breaks are represented by \r\n
. When you write a \n
to the text stream, it gets written as \r\n
.
To write raw binary data, you need to open the stream as a binary stream. This is done by passing the ios_base::binary
flag to the constructor of the stream.
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