Is there a simple way to do URL encode in C? I'm using libcurl but I haven't found a method. Specifically, I need to do percent escapes.
URL encoding converts characters into a format that can be transmitted over the Internet. - w3Schools. So, "/" is actually a seperator, but "%2f" becomes an ordinary character that simply represents "/" character in element of your url.
A space is assigned number 32, which is 20 in hexadecimal. When you see “%20,” it represents a space in an encoded URL, for example, http://www.example.com/products%20and%20services.html.
%23 is the URL encoded representation of # . I suspect your rewrite rules will not satisfy %23 . You ought to investigate how the response is being constructed. Specifically, any URL encoding functions.
In C based on wikipedia, without having to alloc and free. Make sure output buffer is at least 3X input URL string. Usually you only need to encode up to maybe 4K as URLs tend to be short so just do it on the stack.
char rfc3986[256] = {0};
char html5[256] = {0};
void url_encoder_rfc_tables_init(){
int i;
for (i = 0; i < 256; i++){
rfc3986[i] = isalnum( i) || i == '~' || i == '-' || i == '.' || i == '_' ? i : 0;
html5[i] = isalnum( i) || i == '*' || i == '-' || i == '.' || i == '_' ? i : (i == ' ') ? '+' : 0;
}
}
char *url_encode( char *table, unsigned char *s, char *enc){
for (; *s; s++){
if (table[*s]) *enc = table[*s];
else sprintf( enc, "%%%02X", *s);
while (*++enc);
}
return( enc);
}
Use it like this
url_encoder_rfc_tables_init();
url_encode( html5, url, url_encoded);
curl_escape
which apparently has been superseded by
curl_easy_escape
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