I'm picking up C# by porting some legacy C++ code and would like to keep the output identical. What used to be something along the lines of
output << std::setprecision(10) << (double) value;
I figured would now be
output.Write("{0:F10}", value);
But this didn't do the trick. Specifically values > 1
would get more digits. A common online suggestion was to Math.Round
first, but this appends zeroes if the total length was < 10
.
So I put together:
// std::setprecision is not exactly the same as ":F10", mirror original behavior
static string setPrecision(double value) {
string ret = value.ToString();
// Don't just Substring(0, 11), we need to apply rounding,
// and don't always do this, we don't want to append zeroes,
// for 10 digits + period, with 0.. not counting for total
if(ret.Length > digits + 1)
ret = Math.Round(value, digits + (value < 1 ? 1 : 0) - ret.IndexOf('.')).ToString();
return ret;
}
where digits
is a static constant; I could certainly make this a variable, but for this project in particular it makes little sense to do so.
Still, this seems overly complicated. Is there a more elegant way to get the traditional behavior?
As requested some example I/O
// C++
double test = 0; out << std::setprecision(10);
test = 0.123456780; out << test << '\n';
test = 0.0123456781; out << test << '\n';
test = 0.11234567819; out << test << '\n';
test = 1.00234567899; out << test << '\n';
// C#
double test = 0;
test = 0.123456780; output.WriteLine(setPrecision(test));
test = 0.0123456781; output.WriteLine(setPrecision(test));
test = 0.11234567819; output.WriteLine(setPrecision(test));
test = 1.00234567899; output.WriteLine(setPrecision(test));
Both produce:
0.12345678
0.0123456781
0.1123456782
1.002345679
And meanwhile I noticed all heading zeroes don't seem to count towards the total rather than just the first;
// C++
test = 0.012345678906; out << test << '\n'; // 0.01234567891
test = 0.0012345678906; out << test << '\n'; // 0.001234567891
test = 0.00012345678906; out << test << '\n'; // 0.0001234567891
// C#
test = 0.012345678906; output.WriteLine(setPrecision(test)); // 0.0123456789
test = 0.0012345678906; output.WriteLine(setPrecision(test)); // 0.0012345679
test = 0.00012345678906; output.WriteLine(setPrecision(test)); // 0.0001234568
I'll have to correct that if there isn't a more straightforward solution.
It sounds like you just want to print the number with a specific number of significant digits. You can simply use the G format string to specify the number of digits to use.
output.Write("{0:G10}", value);
What you are referring to is significant figures. It's actually pretty easy to calculate:
public static string FormatSignificantFigures(double number, int figures)
{
int e = 0;
while (number >= 10.0)
{
e += 1;
number /= 10;
}
while (number < 1.0)
{
e -= 1;
number *= 10;
}
figures--;
number = Math.Round(number, figures);
figures += 0 - e;
while (e > 0)
{
number *= 10;
e -= 1;
}
while (e < 0)
{
number /= 10;
e += 1;
}
if (figures < 0)
{
figures = 0;
}
return number.ToString($"f{figures}");
}
Basically, the first two while
loops normalize our number to a value between [1,10)
.
Then, we round the number to the number of significant figures (minus 1, remembering that we already have a significant figure of 1
at the front). We then restore it, and the last line is a C#6.0 string interpolation for:
return number.ToString("f" + figures);
The test code was:
public static void _Main(string[] args)
{
double[] numbers = new double[] { 0.012345678906, 0.0012345678906, 0.00012345678906, 0.123456789012, 1.234567890124, 12.345678901234, 123.45678901234, 1234.5678901234, 12345.678901234 };
foreach (double number in numbers)
{
Console.WriteLine($"{number}: {FormatSignificantFigures(number, 3)}");
}
}
Results:
0.012345678906: 0.0123 0.0012345678906: 0.00123 0.00012345678906: 0.000123 0.123456789012: 0.123 1.234567890124: 1.23 12.345678901234: 12.3 123.45678901234: 123 1234.5678901234: 1230 12345.678901234: 12300
Note: this was a quick answer, I'm going to extract some of this out to another function which doesn't return a string momentarily, but this should get you started.
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