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What does it mean to call a class like this:
class Example
{
public:
Example(void);
~Example(void);
}
int main(void)
{
Example ex(); // <<<<<< what is it called to call it like this?
return(0);
}
Like it appears that it isn't calling the default constructor in that case. Can someone give a reason why that would be bad?
Thanks for all answers.
599
There can be multiple constructors in a class. However, the parameter list of the constructors should not be same. This is known as constructor overloading.
The default constructor does only shallow copy. Deep copy is possible only with a user-defined copy constructor. In a user-defined copy constructor, we make sure that pointers (or references) of copied objects point to new memory locations.
The default copy constructor will copy all members – i.e. call their respective copy constructors. So yes, a std::vector (being nothing special as far as C++ is concerned) will be duly copied.
If any constructor is explicitly declared, then no default constructor is automatically generated. If a virtual destructor is explicitly declared, then no default destructor is automatically generated.
Currently you are trying to call the default constructor like so.
Example ex();
This is not actually calling the default constructor. Instead you are defining a function prototype with return type Example and taking no parameters. In order to call the default constructor, omit the ()'s
Example ex;
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