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What is the difference between the two declarations in case of foo's arguments? The syntax in the second one is familiar to me and declares a pointer to function. Are both declarations fully equivalent?
void foo(int(int));
void foo(int(*)(int));
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The following is the syntax for the declaration of a function pointer: int (*FuncPtr) (int,int);
Declare a variable x of the integer datatype. Print the value of varisble x. Declare a pointer p of the integer datatype. Define p as the pointer to the address of show() function.
Function pointers in C need to be declared with an asterisk symbol and function parameters (same as function they will point to) before using them in the program. Declaration of function pointers in C includes return type and data type of different function arguments.
The * refers to the return type of the function, which is void * .
They are equivalent as long as int(int) and int(*)(int) are used in function parameter lists. In function parameter list the int(int) is automatically adjusted by the language to mean int(*)(int).
It is the same adjustment mechanism that makes int [] parameter declaration equivalent to int * parameter declaration.
Outside of this specific context int(int) and int(*)(int) mean two different things.
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