C++ obtaining milliseconds time on Linux -- clock() doesn't seem to work properly

Question

On Windows, clock() returns the time in milliseconds, but on this Linux box I'm working on, it rounds it to the nearest 1000 so the precision is only to the "second" level and not to the milliseconds level.

I found a solution with Qt using the QTime class, instantiating an object and calling start() on it then calling elapsed() to get the number of milliseconds elapsed.

I got kind of lucky because I'm working with Qt to begin with, but I'd like a solution that doesn't rely on third party libraries,

Is there no standard way to do this?

UPDATE

Please don't recommend Boost ..

If Boost and Qt can do it, surely it's not magic, there must be something standard that they're using!

Answer 1

#include <sys/time.h>
#include <stdio.h>
#include <unistd.h>
int main()
{
    struct timeval start, end;

    long mtime, seconds, useconds;    

    gettimeofday(&start, NULL);
    usleep(2000);
    gettimeofday(&end, NULL);

    seconds  = end.tv_sec  - start.tv_sec;
    useconds = end.tv_usec - start.tv_usec;

    mtime = ((seconds) * 1000 + useconds/1000.0) + 0.5;

    printf("Elapsed time: %ld milliseconds\n", mtime);

    return 0;
}

Answer 2

Please note that clock does not measure wall clock time. That means if your program takes 5 seconds, clock will not measure 5 seconds necessarily, but could more (your program could run multiple threads and so could consume more CPU than real time) or less. It measures an approximation of CPU time used. To see the difference consider this code

#include <iostream>
#include <ctime>
#include <unistd.h>

int main() {
    std::clock_t a = std::clock();
    sleep(5); // sleep 5s
    std::clock_t b = std::clock();

    std::cout << "difference: " << (b - a) << std::endl;
    return 0;
}

It outputs on my system

$ difference: 0

Because all we did was sleeping and not using any CPU time! However, using gettimeofday we get what we want (?)

#include <iostream>
#include <ctime>
#include <unistd.h>
#include <sys/time.h>

int main() {
    timeval a;
    timeval b;

    gettimeofday(&a, 0);
    sleep(5); // sleep 5s
    gettimeofday(&b, 0);

    std::cout << "difference: " << (b.tv_sec - a.tv_sec) << std::endl;
    return 0;
}

Outputs on my system

$ difference: 5

If you need more precision but want to get CPU time, then you can consider using the getrusage function.

Answer 3

You could use gettimeofday at the start and end of your method and then difference the two return structs. You'll get a structure like the following:

struct timeval {
  time_t tv_sec;
  suseconds_t tv_usec;
}

EDIT: As the two comments below suggest, clock_gettime(CLOCK_MONOTONIC) is a much better choice if you have it available, which should be almost everywhere these days.

EDIT: Someone else commented that you can also use modern C++ with std::chrono::high_resolution_clock, but that isn't guaranteed to be monotonic. Use steady_clock instead.

Answer 4

I also recommend the tools offered by Boost. Either the mentioned Boost Timer, or hack something out of Boost.DateTime or there is new proposed library in the sandbox - Boost.Chrono: This last one will be a replacement for the Timer and will feature:

• The C++0x Standard Library's time utilities, including:
  • Class template duration
  • Class template time_point
  • Clocks:
    • system_clock
    • monotonic_clock
    • high_resolution_clock
• Class template timer, with typedefs:
  • system_timer
  • monotonic_timer
  • high_resolution_timer
• Process clocks and timers:
  • process_clock, capturing real, user-CPU, and system-CPU times.
  • process_timer, capturing elapsed real, user-CPU, and system-CPU times.
  • run_timer, convenient reporting of |process_timer| results.
• The C++0x Standard Library's compile-time rational arithmetic.

Here is the source of the feature list