c++ new and delete overloading

Question

new and delete operator overloading might or might not work when compiled using different compilers and different c++ standards. Is that the normal behavior?

I used the following code to test the compilers.

#include <iostream>

void * operator new(size_t size)
{
    std::cout << "1\n";
    return malloc(size);
}

void operator delete(void *ptr) noexcept
{
    std::cout << "2\n";
    free(ptr);
}

int main(void)
{
    int *n1 = new int;
    delete n1;

    int *n2 = new int[10];
    delete[] n2;

    return 0;
}

Here are the results I got from several compilers I have tested the code on.

mingw-w64 official build - x86_64-7.1.0-release-posix-seh-rt_v5-rev0.7z

c++11
1
2

c++14
1

clang x86_64 - v4.0.0 manually built without patches using the compiler above

c++11 and c++14
1
2

msvc - platform toolset v141 & sdk v10.0.15063.0

/std:c++14 and /std:c++latest
1
2
1
2

All tests are performed on Windows 7. I can't test compilers on GNU/Linux OS because I don't have any VMs set up.

Answer 1

By the standard, the default behavior of both operator new[] is ([new.delete.array]/4):

Returns operator new(size), or operator new(size, alignment), respectively.

Something similar goes for operator delete[] ([new.delete.array]/15):

The functions that have a size parameter forward their other parameters to the corresponding function without a size parameter. The functions that do not have a size parameter forward their parameters to the corresponding operator delete (single-object) function.

The default versions of these functions simply call the non-array forms. Therefore, Visual Studio and GCC 6.3 are correct: overloading just the non-array versions should be enough to overload the allocators.