C# LINQ: remove null values from an array and return as not nullable

Question

I'm converting nullable array to unnullable. This is my current code with two function calls:

myarray.Where(e => e.HasValue).Select(e => e.Value)

It looks like a very basic operation. Is it possible to do that in one call?

Answer 1

myarray.OfType<int>();

This works because nullable types box to their underlying types if they are not null, but don't if they are null.

EDIT: The only thing I'll point out is that the semantics of the one-liner I made are slightly different than yours. It could be that you'd want yours instead of mine. Your code: "grab all nullable objects which have a value". My code: "grab all types which can successfully be cast to int"

Answer 2

You can always make your own extensions but that only makes your code seem more succinct, think that your implementation is the most succinct and clear you can get to be honest

public static IEnumerable<T> GetNonNullValues<T>(this IEnumerable<Nullable<T>> items) where T: struct
{
    return items.Where(a=>a.HasValue).Select(a=>a.Value);
}

Answer 3

try using .OfType(...)

Example...

myarray.OfType<int>()

... this worked for me ...

var d = new int?[] { 1, 2, 3, 4, 5, null, null, 6, 7, 8, 9, null };
Console.WriteLine(d.Count()); // 12
Console.WriteLine(d.OfType<int>().Count()); //9