Is it possible to return an IOrderedEnumerable<T>
from a method without using the OrderBy
or OrderByDescending
methods on an IEnumerable<T>
?
Im guessing perhaps not... but... maybe I am wrong?
Reason: Mostly curiosity. It just kind of hit me when making this answer on returning digits in a number. And my method would return the digits in ascending order, according to their weight in the given number. So I thought it could be nice if they came out ordered in a way that the framework would recognize as ordered as well. Of course we can argue that from a common number point of view they were not ordered. But yeah... if they should or shouldn't wasn't the point here. Just if it was possible or not.
I guess I am also kind of implying a question (or am now at least) on if an IOrderedEnumerable<T>
is more than just an IEnumerable<T>
with a different name. Does it contain anything more? i know it has the ThenBy
and ThenByDescending
methods, but do they use anything inside the IOrderedEnumerable<T>
, or is it just that they don't make sense to use directly on an IEnumerable<T>
?
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In the real sense it has no meaning or full form. It was developed by Dennis Ritchie and Ken Thompson at AT&T bell Lab. First, they used to call it as B language then later they made some improvement into it and renamed it as C and its superscript as C++ which was invented by Dr. Stroustroupe.
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Well, you can implement IOrderedEnumerable<T>
yourself if you want too... it's not hugely hard, depending on what you need to do. The easiest option is just to call OrderBy
/OrderByDescending
though :)
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