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c++ initialize array with declared size as a value of an integer

Tags:

c++

arrays

I want to initialize an array with a size using a value I read into an integer variable. I cant seem to understand why it works in Dev-C++ but not in Turbo C++. Here's the code to help make things clear

int arr_size; //cin max value for lets say number of students or something...
cin >> arr_size;
int array[arr_size]; // declares array with size (assume 10 or 100) with range 0 to 9 or 0-99

The compiler shows an error in Turbo C++ (really old, I know, but my school uses it unfortunately). Dev-C++ and codeblocks doesnt.

Why is that so? I know its bad practice "as they define it in some books" to have an array size the same as an int value, but is there a work around for this in Turbo C++? I want to know why the error happens and how I can get a work around it ... thanks a lot!

like image 778
Yogi Cplusplus Avatar asked Jul 18 '26 09:07

Yogi Cplusplus


1 Answers

The C++ standard only permits arrays to be sized with a constant expression. (However, some compilers may offer it as a non-standard language extension.)

You could use a std::vector instead:

std::vector<int> array(arr_size);

Or you could dynamically-allocate memory manually:

int *const array = new int[arr_size];

...

delete [] array;  // Remember to delete when you're done
like image 100
Oliver Charlesworth Avatar answered Jul 21 '26 00:07

Oliver Charlesworth