C# How to XOR all int elements of an array after reading from console?

Question

My real purpose is to get the only array element that appears odd number of times. So I found out it can be done via XOR-ing all elements of the array. Like this:

int[] arr = { 3, 4, 7, 7, 0, 4, 0, 7, 3 };
Console.WriteLine(arr[0] ^ arr[1] ^ arr[2] ^ arr[3] ^ arr[4] ^ arr[5] ^ arr[6] ^ arr[7] ^ arr[8]);

The problem however is that the array is not given, but is being read from the console, thus I don't know how to XOR the elements after they are entered. The code I could work out so far is:

EDIT: I managed to finish the code properly, thanks to your help.

static void Main()
        {                
        int N = int.Parse(Console.ReadLine());
        long[] rectArray = new long[N];           

        for (int i = 0; i < N; i++)
        {
            rectArray[i] = long.Parse(Console.ReadLine());
        }
        long initial = rectArray[0]; 
        for (int i = 1; i < rectArray.Length; ++i)
        {
            initial ^= rectArray[i];
        }            
        Console.WriteLine(initial);
        }
}

P.S I'm real noob, so please be patient! :)

Answer 1

Along the same lines as Esailija's answer, but using foreach - taking advantage of the fact that 0 ^ x == x for all values of x:

int current = 0;
foreach (int value in array)
{
    current ^= value;
}
Console.WriteLine(current);

EDIT: As noted in comments, LINQ's Aggregate method will do this too - and as we're happy to use the first two values in the first step, we don't even need to provide a seed:

int xor = array.Aggregate((x, y) => x ^ y);

Answer 2

You could write a loop:

int initial = 0;
for( int i = 0; i < arr.Length; ++i ) {
    initial ^= arr[i];
}
Console.WriteLine( initial );

Answer 3

for (int i = 0; i < rectArray.Length; i++)
{                      
    sum ^= rectArray[i];
}