C# How to divide decimals without implicit round up

Question

In c# when you perform the division of two decimals the last digit of the result will automatically be rounded if the true mathematical result cannot be exactly stored as a decimal type.

I want to write a function that performs the division where the last digit is always rounded down even if the digit to the right of the last would normally cause a round up.

My function would be declared as MyDivide(decimal a, decimal b)

As an example MyDivide(2.0M, 3.0M) => 0.6666666666666666666666666666

whereas the c# division operator would yield 2.0M / 3.0M => 0.6666666666666666666666666667

Any help implementing this is appreciated.

Answer 1

You're going to have to implement long division yourself. There is NO way to finagle the built-in division into doing this for you (hint: you can't distinguish between 2m / 3m and .6666666666666666666666666667m / 1m or 6666666666666666666666666667m / 10000000000000000000000000000m for that matter).