c++ functions as parameters without pointers

Question

When searching for how to pass functions as parameters in C++, I only find examples that use function pointers. However the following compiles and outputs "g20" as expected in Visual Studio. Is it better to declare f like this:

f(void (*fun)());

instead of

f(void fun());

my example:

#include <iostream>

using namespace std;

int f(void fun());
void g();

int main() {
    cout << f(g);
}

void g() {
    cout << "g";
}

int f(void fun()) {
    fun();
    return 20;
}

Answer 1

You might prefer std::function<> instead of function pointers. It can not only store function pointers, but also lambdas, bind expressions, function objects (objects with operator()), etc. Especially the lambdas will make your API a lot better usable.

int f(std::function<void()>& fun) {
    fun();
    return 20;
}