What I need is a method that can return a type (no object, cause no casting allowed) following a condition. Here is an example:
??? right (string fullStr, int endPosition)
{
string tmpStr = "";
tmpStr = fullStr.Substring(endPosition);
if(tmpStr.Length == 1)
return tmpStr[0]; //return a char!!
else
return tmpStr; //return a string!!
}
I tried generics but I was only able to return the type that was coming in, (if a char came in a char was returned, and if a string came in a string was returned). I tried this:
public static T right<T>(T stringToCheck, int endPosition)
{
if (typeof(T).ToString() == "System.String")
{
string fullString = (string)((object)stringToCheck);
string response = "";
response = fullString.Substring(endPosition);
if (response.Length == 1)
{
return (T)((object)response[0]);
}
else
return (T)((object)response);
}
return stringToCheck;
}
I can't use typecasting (returning an object), cant use ref params.
Calls to the method have to stay the same:
right(stringOrChar,int) -> returns string or char.
Thank You
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I don't think it's theoretically possible. You could use "dynamic" in C# 4, but if you're not there yet, you can't do that.
If it could return either a string or a character, then it has to be an object that both of those descend from, of which "object" is your only choice. And then you'd have to do casts.
C# (3.5 and previous) needs to know what the single return type of the method is so that it can do checking on the calling method. And in fact, in C#4, when you say "dynamic" it actually uses "object" underneath.
You could create a custom class/struct that has both
public class StringOrChar
{
char charValue;
string stringValue;
bool isString;
}
But it's kludgy.
Why do you want to have different return types?
The return type of a function must be typed. As with any other variable or operation, any type that inherits from the specified type is a valid return value (which is why object
allows anything as a value).
The logistics of the caller wouldn't make much sense; how would you know whether to type your variable as a char
or a string
in your example?
Is there a particular reason that you can't return a string
in all cases?
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