C - dynamic function call without a function pointer

Question

I would like to call C functions (e.g. form the stdlib, math ...) dynamically. This means that my C program only knows the pointer to a random function (e.g. printf) and its signature (coded as a char array: char *, ...).

My goal is a reflectCall-function that gets a pointer to a function (&printf), a signature (somehow coded in a char[]), and the parameters as a long[] (long is not the actual datatype, one long value can also represent a double value, pointer,...).

The signature of my reflect function therefore looks like this:

long reflectCall(void *funcPointer, char[] types, long[] args)

The function should do the actual call of the function *funcPointer and finally return its result.

As a result, I can not create a pointer pointer; e.g. like this one:

int (*functionPtr)(int,int);

Can anybody give me a hint how to solve this problem or suggest any reference implementation?

Answer 1

It is possible to do it in pure C but it is not so simple and not so quick:

1. Create wrapper functions for all functions you want to call, such as:

   int WrapPrintf(const char* types,long* args,long* results)
   {
       // Function specific code, in this case you can call printf for each parameter
       while(*types)
       {
           switch(*types){
           case 'i':
               printf("%d",(int)*args);
               break;
           case 'c':
               printf("%c",(char)*args);
               break;
           // .. and so on
           }
   
           ++types;
           ++args;
       }
       // Return number of filled results
       return 0;
   }
   
   int WrapFoo(const char* types,long* args,long* results)
   {
       // ..function specific code..
       return 0;
   }
   

2. Pointer to a wrapper function:

   typedef int (*TWrapper)(const char*,long*,long*);
   

3. Create a table structure for wrapped functions:

   struct STableItem{
       const char *strName;
       TWrapper pFunc;
   };
   

4. Create a table:

   STableItem table[] = {
       {"printf", &WrapPrintf},
       {"foo", &WrapFoo},
       {NULL, NULL}
   };
   

5. Create interface to call any function from the table (search function by name and call it):

   int DynamicCall(const char *func_name,const char* types,long* args,long* results)
   {
       int k;
       for(k=0;table[k].strName != NULL;++k){
           if(strcmp(func_name,table[k].strName) == 0){
               return table[k].pFunc(types,args,results);
           }
       }
   
       return -1;
   }
   

6. And finally make a call:

   long args[] = {123,'b'};
   long results[8];            // not nice but just for an example
   
   int res_count = DynamicCall("printf","ic",(long*)args,(long*)results);
   

Note: use a hash function for quicker name search

Answer 2

C does not provide the facilities to do this. You'd have to write the body of the function in platform-specific ASM.

Answer 3

I would to recommend you to look at libffi, whether it fits your needs...

http://sourceware.org/libffi/
http://en.wikipedia.org/wiki/Libffi

Answer 4

As explained elsewhere, there is no way to do this truly dynamically. However, if you wish to build a table of functions using pointers, and use some sort of string or index to describe what you want to do, then that would certainly be possible, in a portable way. This is not at all uncommon as a solution for various parsing and other "run code based on commands, etc".

But it does require that you use a function pointer of some sort [or cast your void * into one at some point or another]. There is no other (even nearly) portable way of calling a function dynamically in C.