c# dictionary get the key of the min value

Question

probably a simple one for you today but I'm currently going round in circles. Consider this scenario:

var tempDictionary = new Dictionary<string, int>();
tempDictionary.Add("user 1", 5);
tempDictionary.Add("user 2", 3);
tempDictionary.Add("user 3", 5);

Console.WriteLine(tempDictionary.Min(x => x.Key) + " => " tempDictionary.Min(x => x.Value);

The above returns "user 1 => 3".

How would you go about returning the key with the lowest value in a dictionary? The output I'm after would look like this instead: "user2 => 3"

Any ideas?

Answer 1

using morelinq

var keyR = tempDictionary.MinBy(kvp => kvp.Value).Key;

or

 var min = tempDictionary.Aggregate((l, r) => l.Value < r.Value ? l : r).Key;

from Highest value of a Dictionary in C#