C# - Create SQL Server table programmatically

Question

I am trying to create a SQL Server table programmatically. Here is the code.

using (SqlConnection con = new SqlConnection(conStr))
{

    try
    {
        //
        // Open the SqlConnection.
        //
        con.Open();
        //
        // The following code uses an SqlCommand based on the SqlConnection.
        //
        using (SqlCommand command = new SqlCommand("CREATE TABLE Customer(First_Name char(50),Last_Name char(50),Address char(50),City char(50),Country char(25),Birth_Date datetime);", con))
            command.ExecuteNonQuery();

    }
    catch (Exception ex)
    {
        MessageBox.Show(ex.Message);
    }
}

When I'm running this application second time I'm getting an exception:

"There is already an object named 'Customer' in the database"

but when I check database I don't see such a table.
Here is my connection string.

<connectionStrings>
  <add name ="AutoRepairSqlProvider" connectionString=
     "Data Source=.\SQLEXPRESS;AttachDbFilename=|DataDirectory|\AutoRepairDatabase.mdf;
     Integrated Security=True;User Instance=True"/>
</connectionStrings>

When I am running select query; I am getting results from existing tables so I think connection string should be OK. Hope you'll see the problem :/

Answer 1

You haven't mentioned the Initial catalog name in the connection string. Give your database name as Initial Catalog name.

<add name ="AutoRepairSqlProvider" connectionString=
     "Data Source=.\SQLEXPRESS; Initial Catalog=MyDatabase; AttachDbFilename=|DataDirectory|\AutoRepairDatabase.mdf;
     Integrated Security=True;User Instance=True"/>

Answer 2

First, check whether the table exists or not. Accordingly, create table if doesn't exist.

var commandStr= "If not exists (select name from sysobjects where name = 'Customer') CREATE TABLE Customer(First_Name char(50),Last_Name char(50),Address char(50),City char(50),Country char(25),Birth_Date datetime)";

using (SqlCommand command = new SqlCommand(commandStr, con))
command.ExecuteNonQuery();