C# Convert.ToDouble() loses decimal points when converting string to double

Question

Let's say we have the following simple code

        string number = "93389.429999999993";
        double numberAsDouble = Convert.ToDouble(number);
        Console.WriteLine(numberAsDouble);

after that conversion numberAsDouble variable has the value 93389.43. What can i do to make this variable keep the full number as is without rounding it? I have found that Convert.ToDecimal does not behave the same way but i need to have the value as double.

-------------------small update---------------------

putting a breakpoint in line 2 of the above code shows that the numberAsDouble variable has the rounded value 93389.43 before displayed in the console.

Answer 1

93389.429999999993 cannot be represented exactly as a 64-bit floating point number. A double can only hold 15 or 16 digits, while you have 17 digits. If you need that level of precision use a decimal instead.

(I know you say you need it as a double, but if you could explain why, there may be alternate solutions)