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C# catch(DataException) - no variable defined

Tags:

c#

catch-block

static void Main(string[] args)
{
    try
    {
        Console.WriteLine("No Error");
    }
    catch (DataException) /*why no compilation error in this line?*/
    {
        Console.WriteLine("Error....");
    }
    Console.ReadKey();
}

The code is compiling without any error. I do not understand why the first line of the catch block is not giving any compilation error -

catch (DataException)

DataException parameter of the catch block is a class, and it should have a variable next to it such as -

catch (DataException d)

Can someone explain the above behavior?

like image 317
Manoj Agarwal Avatar asked Sep 15 '15 01:09

Manoj Agarwal


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1 Answers

In section 8.10 of the C# 5.0 spec, you'll find the syntax definition for try/catch (apologies for the formatting):

catch-clauses:
    specific-catch-clauses       general-catch-clauseopt
    specific-catch-clausesopt   general-catch-clause
specific-catch-clauses:
    specific-catch-clause
    specific-catch-clauses    specific-catch-clause
specific-catch-clause:
    catch    (    class-type    identifieropt    )    block
general-catch-clause:
    catch    block

So you can see that catch { }, catch (Exception) { } and catch (Exception ex) { } are all valid according to the specification.

If you don't specify the optional identifier in the catch block, then you're not able to access any exception details - but sometimes you don't need to, so it's good to not declare a variable you don't intend to access.

like image 147
Blorgbeard Avatar answered Oct 27 '22 02:10

Blorgbeard