C++, can I statically initialize a std::map at compile time?

Question

If I code this

std::map<int, char> example = {                                 (1, 'a'),                                 (2, 'b'),                                 (3, 'c')                                }; 

then g++ says to me

deducing from brace-enclosed initializer list requires #include <initializer_list> in C++98 ‘example’ must be initialized by constructor, not by ‘{...}’    

and that annoys me slightly because the constructor is run-time and can, theoretically fail.

Sure, if it does, it will fail quickly and ought to do so consistently, so that I ought to quickly locate & correct the problem.

But, still, I am curious - is there anyway to initialize map, vector, etc, at compile time?

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Edit: I should have said that I am developing for embedded systems. Not all processors will have a C++0x compiler. The most popular probably will, but I don't want to encounter a gotcha & have to maintain 2 versions of the code.

As to Boost, I am undecided. They are wishy-washy on the use of their Finite State Machine classes in embedded systems, so that is actually what I am coding here, Event/State/Fsm classes.

Sigh, I guess I'd better just play it safe, but I hope that this discussion has been helpful for others.

Answer 1

It's not exactly static initialization, but still, give it a try. If your compiler doesn't support C++0x, I'd go for std::map's iteration constructor:

std::pair<int, std::string> map_data[] = {     std::make_pair(1, "a"),     std::make_pair(2, "b"),     std::make_pair(3, "c") };  std::map<int, std::string> my_map(map_data,     map_data + sizeof map_data / sizeof map_data[0]); 

This is pretty readable, doesn't require any extra libraries and should work in all compilers.