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C# 4.0 Optional Parameters - How to Specify Optional Parameter of Type "Guid"?

Here's my method:

public void SomeQuery(string email = "", Guid userId = Guid.Empty)
{
   // do some query
}

userId is giving me an error as it must be a compile-time constant, which i understand. But even when i declare a const:

private const emptyGuid = Guid.Empty;

then change the method signature to:

public void SomeQuery(string email = "", Guid userId = emptyGuid)
{
   // do some query
}

still no love.

What am i missing?

like image 708
RPM1984 Avatar asked Aug 04 '10 00:08

RPM1984


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2 Answers

Have you tried setting it to a new instance of Guid ala:

public void SomeQuery(string email = "", Guid userId = new Guid())
{
   // do some query
}

Should do the trick.

like image 98
Quintin Robinson Avatar answered Sep 20 '22 12:09

Quintin Robinson


Wouldn't a better solution be to overload the method with a version that doesn't require the Guid? This would solve the issue, and would be a better design in my opinion. Of course, there may be other constraints that I am unaware of necessitating this design.

like image 24
sgriffinusa Avatar answered Sep 18 '22 12:09

sgriffinusa