Byte typecasting

Question

It is a basic question, but I couldn't get a the proper answer. I am thinking it is because of primitive types auto type casting

Why would the below statement invokes the print(int x) method and not print (char x) method.

public class Overloading {

    public static void main(String args[])
    {
        byte b='x';
        print(b);
    }

    public static void print(int x)
    {
        System.out.println("Inside int Print "+x);
    }


    public static void print(char x)
    {
        System.out.println("Inside char Print "+x);
    }

    public static void print(float x)
    {
        System.out.println("Inside float Print "+x);
    }


}

Answer 1

The conversion that may be used for this method invocation conversion is a widening primitive conversion :

byte to short, int, long, float, or double

short to int, long, float, or double

char to int, long, float, or double

int to long, float, or double

long to float or double

float to double

You see there is no byte to char path. This isn't a priority matter : if you remove the function taking an int as parameter, your code won't compile.