I am reading a row from a SQL Server table. One of the columns is of type tinyint.
I want to get the value into an int or int32 variable.
rdr.GetByte(j)
(byte) rdr.GetValue(j)
...seems to be the only way to retrieve the value. But how do I get the result into an int
variable?
int value = rdr.GetByte(j);
An explicit cast is not required, because a byte
to int
is a widening conversion (no possibility of data loss).
See the documentation for BitConverter.ToInt32 (contains more examples):
byte[] bytes = { 0, 0, 0, 25 };
// If the system architecture is little-endian (that is, little end first),
// reverse the byte array.
if (BitConverter.IsLittleEndian)
Array.Reverse(bytes);
int i = BitConverter.ToInt32(bytes, 0);
Console.WriteLine("int: {0}", i);
// Output: int: 25
Assigning a byte
to an int
works:
int myInt = myByte;
But maybe you're getting an exception inside IDataRecord.GetByte
, in which case you should check that the index you're using to access the data record really points to a tinyint
column. You can check the type returned from GetValue
. It should be a byte
for a tinyint
column.
Trace.Assert(rdr.GetValue(j).GetType() == typeof(byte));
Another option is to forego the fragile numeric index altogether:
int myInt = rdr.GetByte(rdr.GetOrdinal(TheNameOfTheTinyintColumn))
(int)rdr.GetByte(j)
Casting the byte to int should work just fine:
int myInt = (int) rdr.GetByte(j);
Since C# supports implicit conversions from byte to int, you can alternatively just do this:
int myInt = rdr.GetByte(j);
Which one you choose is a matter of preference (whether you want to document the fact that a cast is taking place or not). Note that you will need the explicit cast if you want to use type inference, or otherwise myInt will have the wrong type:
var myInt = (int) rdr.GetByte(j);
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