Build only default (no flavors/variants)

Question

I have a bunch of product flavors defined for my build. However in some scenarios I want to build without a flavor.

However when I try to build a release with no flavor, ie

gradlew assembleRelease

It goes through and builds all of the variants, which takes a really long time. I would like to kick off a release build and ignore all flavors. Is that possible?

I am sure I could add an empty flavor called 'default, and build that. Seems like I should not have to do that.

EDIT:

defaultConfig {
    resValue "string", "hello", "Hello default"
}

productFlavors {
    foo {
        resValue "string", "hello", "Hello Foo"
    }

    bar {
        resValue "string", "hello", "Hello Bar"
    }
}

Seems the answer at the moment is to provide your own 'default' flavor

productFlavors {

    defaults {
       // yup its empty cause I just want to build with the defaults
       // that are already defined.
    }

    foo {
        resValue "string", "hello", "Hello Foo"
    }

    bar {
        resValue "string", "hello", "Hello Bar"
    }
}

Answer 1

I found out that "main" as a flavor works. So i dont need to add an additional folder with google-services.json or anything in it

productFlavors {

    main{

    }

    flav1 {
        applicationId 'id'
    }

}