Break servlet-filter work

Question

I have SecurityAuthorisationFilter and the following part of the code:

for(String anonymousRequestURI : anonymousRequestURIs) {
     if(httpRequest.getRequestURI().equals(anonymousRequestURI)) {
         //allow request
     }
 }
 String authToken = getTokenFromRequest(httpRequest);

If equals is true I need to skip all next filter operations and send request to controller. But, if I write filterChain.doFilter(servletRequest, servletResponse), there is no result. The filter continue operations to find a token. How can I break out of the filter?

Answer 1

As I understand from your comment, you wish to "break out" of the current filter if the condition about anonymous request URI is true. You could simply return; after calling chain.doFilter():

for ( String uri : anonURIs ) {
    if ( ... ) {
        chain.doFilter( ... );
        return;
    }
}

String authToken = getTokenFromRequest( httpRequest );
...

Cheers,

Answer 2

Well if breakdoesn't give you what you need you can change your loop like this:

int i=0;
do {
      anonymousRequestURI = anonymousRequestURIs[i];
      i++;
while(!httpRequest.getRequestURI().equals(anonymousRequestURI) && i<anonymousRequestURIs.length);
String authToken = getTokenFromRequest(httpRequest);