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boost::trim each string in std::vector<std::string>

I'm currently stuck finding the correct syntax for trimming each string in a std::vector.

I tried

std::vector<std::string> v;
std::for_each(v.begin(), v.end(), &boost::trim);

which gave me the following error messages in MSVC7.1.

error C2784: '_Fn1 std::for_each(_InIt,_InIt,_Fn1)' : could not deduce template argument for 'T1' from 'std::vector<_Ty>::iterator' with [_Ty=std::string] : see declaration of 'std::for_each'

error C2896: '_Fn1 std::for_each(_InIt,_InIt,_Fn1)' : cannot use function template 'void boost::algorithm::trim(SequenceT &,const std::locale &)' as a function argument : see declaration of 'boost::algorithm::trim'

If I explicitly give the template parameter trims second parameter can not be found by the compiler, though its set by default.

std::for_each(v.begin(), v.end(), &boost::trim<std::string>);

error C2198: 'void (__cdecl *)(std::string &,const std::locale &)' : too few arguments for call through pointer-to-function

I was wondering how the correct syntax to call trim for each element in v would look like.

like image 454
Norbert Avatar asked Feb 08 '10 13:02

Norbert


1 Answers

You need to bind as well the second parameter of trim (the locale):

std::vector<std::string> v;
std::for_each(v.begin(), v.end(), 
              boost::bind(&boost::trim<std::string>,
                          _1, std::locale() ));
like image 101
Manuel Avatar answered Nov 11 '22 10:11

Manuel