bit operators with unsigned characters

Question

unsigned char x = 93;
unsigned char a = x << 4;
printf("a = %d\n", a);

I do understand how bit operators work but I don't understand the binary representation of x.

How is a = 208?

Answer 1

93 = 01011101

Shift that left 4 bits and it leaves the following (only 8 bits in your result):

11010000 = 208

Answer 2

x = 93 = 0x5D = 0101 1101
         << 4 = 1101 0000

1101 0000 in decimal is 208.